![]() ![]() Normally, I would need to create the branch before I could check it out, but in newer versions of git, it's smart enough to know that you want to checkout a local copy of this remote branch. To switch to this branch, I can simply run: git checkout my-bugfix-branch Now git knows about my new my-bugfix-branch. * my-bugfix-branch -> origin/my-bugfix-branchįirst, rewinding head to replay your work on top of it.įast-forwarded master to 4316d296c55ac2e13992a22161fc327944bcf5b8. It will display an output that looks something like this: From :andrewhavens/example-project This will fetch all of the remote branches and merge the current branch. If I want to fetch the remote branches, I simply run: git pull My usual workflow is a little different now. I've learned a lot and git has improved since then. ![]() Dell Command Update is a stand-alone application for client systems, that provides updates for system software that is released by Dell. Update: It's been 5 years since I originally posted this question. This Universal Windows Platform (UWP) package contains the Dell Command Update for systems running the Windows 10 build 14393 (Redstone 1) or later. The latter will create a branch that is also set to track the remote branch. Or you can do: git checkout -t origin/branch-name git checkout -b newlocalbranchname origin/branch-name Thanks to a related question, I found out that I need to "checkout" the remote branch as a new local branch, and specify a new local branch name. ![]()
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